99 LT, 4dr, 5.7, 3.43 *or 3.42* 4l60, 148k miles, rear AC, leather.
Stock everything. Just got it about a month ago because it had new front tires.
New water pump, radiator, thermostat, plugs, fuel filter, plugs, dizzy cap and rotor, lower intake gasket set, rebuilt the rear end with new pinion bearings and crush sleeve with Morrie's in the rear, ac compressor, drier, orifice tube, seat leathers, windshield, inside door handles, turned rotors, new brakes, and radio fade and balance knobs...
And i'm still only in the whole rig for under $3000. The body is in PERFECT condition. I practically stole it from the PO because i could rebuild the rear end and AC system my self.
I was hoping to get some advice on getting as much as i could out of this 5.7 MPG wise with measurable results that have a pretty quick return on investment..
If i'm getting 18 mpg now at $3.75 a gallon then i'm paying $.208 a mile.
Say a cold air intake and dual exhaust cost me $400, and my MPG only improves at high end of 20%.
That would move it up to 21.6 mpg ending up at .173 a mile
I would only have to drive about 2400 miles to break even on getting the upgrade.
At the way my wife drives of about 1 tank a week, 27 gallons would get me 486 miles on the old setup at $101.25
The same 27 gallons would get me 583 miles on the same $101.25 on the new setup.
Thats $20.25 a week savings on gas per mpg.
It would take me 20 weeks to recoup the cost of the upgrade.
Is it worth laying out that cash when i will only see a return of that money after 6 months?
Maybe my math is off.
So "is chipping the motor or electric fans or cold air or a Magnaflow cat back WORTH it?"
Just curious............. Its hard to find out for sure..
---------- Post added at 08:19 PM ---------- Previous post was at 08:15 PM ----------
---------- Post added at 09:19 PM ---------- Previous post was at 08:19 PM ----------
I guess you have to find the break over point, or return on investment
Cost of improvements / (((Old cost per mile X Miles per tank) X Miles driven a week) - ((New cost per mile X Miles per tank) x Miles driven a week)) = Weeks to break even.
y = Cost of improvments
a = Old cost per mile
b = Gallons per tank
c = Miles driven a week
d = New cost per mile
z = Weeks to break even
y / (((a X b) x c) -((d x b) x c)) = z
I think.... right?